(x-1)/2=1-(3x-12)/3

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Solution for (x-1)/2=1-(3x-12)/3 equation:



(x-1)/2=1-(3x-12)/3
We move all terms to the left:
(x-1)/2-(1-(3x-12)/3)=0
We calculate fractions
x/()+(-(1-(3x-12)*2)/()=0
We calculate terms in parentheses: +(-(1-(3x-12)*2)/(), so:
-(1-(3x-12)*2)/(
We multiply all the terms by the denominator
-(1-(3x-12)*2)
We calculate terms in parentheses: -(1-(3x-12)*2), so:
1-(3x-12)*2
determiningTheFunctionDomain -(3x-12)*2+1
We multiply parentheses
-6x+24+1
We add all the numbers together, and all the variables
-6x+25
Back to the equation:
-(-6x+25)
We get rid of parentheses
6x-25
Back to the equation:
+(6x-25)
We get rid of parentheses
x/()+6x-25=0
We multiply all the terms by the denominator
x+6x*()-25*()=0
We add all the numbers together, and all the variables
x+6x*()=0

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