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(x-1)/x=x/(3x-5)
We move all terms to the left:
(x-1)/x-(x/(3x-5))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (3x-5))!=0We calculate fractions
x∈R
-2x^2)+(-(x*x)/(-2x^2)+((x-1)*(3x-5)))/(=0
We add all the numbers together, and all the variables
-2x^2)+(-(+x*x)/(-2x^2)+((x-1)*(3x-5)))/(=0
We calculate fractions
-2x^2)+(+(-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x-1)*(3x-5)))*()/((-2x^2)*()=0
We calculate terms in parentheses: +(-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x-1)*(3x-5)))*()/((-2x^2)*(), so:
-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x-1)*(3x-5)))*()/((-2x^2)*(
We can not solve this equation
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