(x-1)2-(x-2)2=(x-4)2-(x-3)2+2

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Solution for (x-1)2-(x-2)2=(x-4)2-(x-3)2+2 equation:



(x-1)2-(x-2)2=(x-4)2-(x-3)2+2
We move all terms to the left:
(x-1)2-(x-2)2-((x-4)2-(x-3)2+2)=0
We multiply parentheses
2x-2x-((x-4)2-(x-3)2+2)-2+4=0
We calculate terms in parentheses: -((x-4)2-(x-3)2+2), so:
(x-4)2-(x-3)2+2
We multiply parentheses
2x-2x-8+6+2
We add all the numbers together, and all the variables

Back to the equation:
-()
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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