(x-1)2-(x-2)2=(x-4)2-(x-3)2+2

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Solution for (x-1)2-(x-2)2=(x-4)2-(x-3)2+2 equation: 



(x-1)2-(x-2)2=(x-4)2-(x-3)2+2

We move all terms to the left:

(x-1)2-(x-2)2-((x-4)2-(x-3)2+2)=0

We multiply parentheses

2x-2x-((x-4)2-(x-3)2+2)-2+4=0



We calculate terms in parentheses: -((x-4)2-(x-3)2+2), so:

(x-4)2-(x-3)2+2

We multiply parentheses

2x-2x-8+6+2

We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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