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(x-1/3)(2x+3)(3x+12)=0
Domain of the equation: 3)(2x+3)(3x+12)!=0We add all the numbers together, and all the variables
x∈R
(+x-1/3)(2x+3)(3x+12)=0
We multiply parentheses ..
(+2x^2+3x-2x^2-1/3*3)(3x+12)=0
We multiply all the terms by the denominator
(+2x^2+3x-2x^2-1=0
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