(x-1/x+2)-(4x-7/5x+10)

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Solution for (x-1/x+2)-(4x-7/5x+10) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(4*x)+(7/5)*x-(1/x)-10+2 = 0

x-4*x+(7/5)*x-x^-1-10+2 = 0

-8/5*x^1-1*x^-1-8*x^0 = 0

(-8/5*x^2-8*x^1-1*x^0)/(x^1) = 0 // * x^2

x^1*(-8/5*x^2-8*x^1-1*x^0) = 0

x^1

(-8/5)*x^2-8*x-1 = 0

(-8/5)*x^2-8*x-1 = 0

DELTA = (-8)^2-(-1*4*(-8/5))

DELTA = 288/5

DELTA > 0

x = ((288/5)^(1/2)+8)/(2*(-8/5)) or x = (8-(288/5)^(1/2))/(2*(-8/5))

x = -5/16*((288/5)^(1/2)+8) or x = -5/16*(8-(288/5)^(1/2))

x in { -5/16*((288/5)^(1/2)+8), -5/16*(8-(288/5)^(1/2))}

x in { -5/16*((288/5)^(1/2)+8), -5/16*(8-(288/5)^(1/2)) }

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