(x-10)(x-6)=x(x+12)

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Solution for (x-10)(x-6)=x(x+12) equation: 



(x-10)(x-6)=x(x+12)

We move all terms to the left:

(x-10)(x-6)-(x(x+12))=0

We multiply parentheses ..

(+x^2-6x-10x+60)-(x(x+12))=0



We calculate terms in parentheses: -(x(x+12)), so:

x(x+12)

We multiply parentheses

x^2+12x

Back to the equation:

-(x^2+12x)



We get rid of parentheses

x^2-x^2-6x-10x-12x+60=0

We add all the numbers together, and all the variables

-28x+60=0

We move all terms containing x to the left, all other terms to the right

-28x=-60

x=-60/-28

x=2+1/7

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