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(x-10)(x=10)
We move all terms to the left:
(x-10)(x-(10))=0
We multiply parentheses ..
(+x^2-10x-10x+100)=0
We get rid of parentheses
x^2-10x-10x+100=0
We add all the numbers together, and all the variables
x^2-20x+100=0
a = 1; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{2}=10$
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