(x-10)+(10-3x)=(3x+14)+(10-3x)

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Solution for (x-10)+(10-3x)=(3x+14)+(10-3x) equation: 



(x-10)+(10-3x)=(3x+14)+(10-3x)

We move all terms to the left:

(x-10)+(10-3x)-((3x+14)+(10-3x))=0

We add all the numbers together, and all the variables

(x-10)+(-3x+10)-((3x+14)+(-3x+10))=0

We get rid of parentheses

x-3x-((3x+14)+(-3x+10))-10+10=0



We calculate terms in parentheses: -((3x+14)+(-3x+10)), so:

(3x+14)+(-3x+10)

We get rid of parentheses

3x-3x+14+10

We add all the numbers together, and all the variables

24

Back to the equation:

-(24)



We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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