(x-10)+(10-3x)=(3x+14)+(10-3x)

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Solution for (x-10)+(10-3x)=(3x+14)+(10-3x) equation:



(x-10)+(10-3x)=(3x+14)+(10-3x)
We move all terms to the left:
(x-10)+(10-3x)-((3x+14)+(10-3x))=0
We add all the numbers together, and all the variables
(x-10)+(-3x+10)-((3x+14)+(-3x+10))=0
We get rid of parentheses
x-3x-((3x+14)+(-3x+10))-10+10=0
We calculate terms in parentheses: -((3x+14)+(-3x+10)), so:
(3x+14)+(-3x+10)
We get rid of parentheses
3x-3x+14+10
We add all the numbers together, and all the variables
24
Back to the equation:
-(24)
We add all the numbers together, and all the variables
-2x-24=0
We move all terms containing x to the left, all other terms to the right
-2x=24
x=24/-2
x=-12

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