(x-10)/3=(2x-)/2

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Solution for (x-10)/3=(2x-)/2 equation: 



(x-10)/3=(2x-)/2

We move all terms to the left:

(x-10)/3-((2x-)/2)=0

We add all the numbers together, and all the variables

(x-10)/3-((+2x)/2)=0

We calculate fractions


x/()+(-((+2x)*3)/()=0



We calculate terms in parentheses: +(-((+2x)*3)/(), so:

-((+2x)*3)/(

We multiply all the terms by the denominator


-((+2x)*3)



We calculate terms in parentheses: -((+2x)*3), so:

(+2x)*3

We multiply parentheses

6x

Back to the equation:

-(6x)



Back to the equation:

+(-6x)



We get rid of parentheses

x/()-6x=0

We multiply all the terms by the denominator


x-6x*()=0

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