(x-10)2=68,x2-20x=-32

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Solution for (x-10)2=68,x2-20x=-32 equation: 



(x-10)2=68.x^2-20x=-32

We move all terms to the left:

(x-10)2-(68.x^2-20x)=0

We multiply parentheses

2x-(68.x^2-20x)-20=0

We get rid of parentheses

-68.x^2+2x+20x-20=0

We add all the numbers together, and all the variables

-68x^2+22x-20=0

a = -68; b = 22; c = -20;
Δ = b2-4ac
Δ = 222-4·(-68)·(-20)
Δ = -4956
Delta is less than zero, so there is no solution for the equation

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