(x-12)/6=(x-6)/12+5

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Solution for (x-12)/6=(x-6)/12+5 equation: 



(x-12)/6=(x-6)/12+5

We move all terms to the left:

(x-12)/6-((x-6)/12+5)=0

We calculate fractions


(12x-144)/()+(-((x-6)*6)/()=0



We calculate terms in parentheses: +(-((x-6)*6)/(), so:

-((x-6)*6)/(

We multiply all the terms by the denominator


-((x-6)*6)



We calculate terms in parentheses: -((x-6)*6), so:

(x-6)*6

We multiply parentheses

6x-36

Back to the equation:

-(6x-36)



We get rid of parentheses

-6x+36

Back to the equation:

+(-6x+36)



We get rid of parentheses

(12x-144)/()-6x+36=0

We multiply all the terms by the denominator


(12x-144)-6x*()+36*()=0

We add all the numbers together, and all the variables

(12x-144)-6x*()=0

We get rid of parentheses

12x-6x*()-144=0

We move all terms containing x to the left, all other terms to the right

12x-6x*()=144

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