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(x-13)(x-5)=(x-10)(x-11)
We move all terms to the left:
(x-13)(x-5)-((x-10)(x-11))=0
We multiply parentheses ..
(+x^2-5x-13x+65)-((x-10)(x-11))=0
We calculate terms in parentheses: -((x-10)(x-11)), so:We get rid of parentheses
(x-10)(x-11)
We multiply parentheses ..
(+x^2-11x-10x+110)
We get rid of parentheses
x^2-11x-10x+110
We add all the numbers together, and all the variables
x^2-21x+110
Back to the equation:
-(x^2-21x+110)
x^2-x^2-5x-13x+21x+65-110=0
We add all the numbers together, and all the variables
3x-45=0
We move all terms containing x to the left, all other terms to the right
3x=45
x=45/3
x=15
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