(x-13)2=(x-12)2+(x-5)2

Solution for (x-13)2=(x-12)2+(x-5)2 equation:

(x-13)2=(x-12)2+(x-5)2

We move all terms to the left:

(x-13)2-((x-12)2+(x-5)2)=0

We multiply parentheses

2x-((x-12)2+(x-5)2)-26=0


We calculate terms in parentheses: -((x-12)2+(x-5)2), so:

(x-12)2+(x-5)2

We multiply parentheses

2x+2x-24-10

We add all the numbers together, and all the variables

4x-34

Back to the equation:

-(4x-34)


We get rid of parentheses

2x-4x+34-26=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4