(x-16)(x-16)=4

Solution for (x-16)(x-16)=4 equation:

(x-16)(x-16)=4

We move all terms to the left:

(x-16)(x-16)-(4)=0

We multiply parentheses ..

(+x^2-16x-16x+256)-4=0

We get rid of parentheses

x^2-16x-16x+256-4=0

We add all the numbers together, and all the variables

x^2-32x+252=0

a = 1; b = -32; c = +252;
Δ = b2-4ac
Δ = -322-4·1·252
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4}{2*1}=\frac{28}{2}
=14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4}{2*1}=\frac{36}{2}
=18
$