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(x-2)(0.5x-4)=-(x-2)(x-4)
We move all terms to the left:
(x-2)(0.5x-4)-(-(x-2)(x-4))=0
We multiply parentheses ..
(+0x^2-4x+0x+8)-(-(x-2)(x-4))=0
We calculate terms in parentheses: -(-(x-2)(x-4)), so:We get rid of parentheses
-(x-2)(x-4)
We multiply parentheses ..
-(+x^2-4x-2x+8)
We get rid of parentheses
-x^2+4x+2x-8
We add all the numbers together, and all the variables
-1x^2+6x-8
Back to the equation:
-(-1x^2+6x-8)
0x^2+1x^2-4x+0x-6x+8+8=0
We add all the numbers together, and all the variables
2x^2-9x+16=0
a = 2; b = -9; c = +16;
Δ = b2-4ac
Δ = -92-4·2·16
Δ = -47
Delta is less than zero, so there is no solution for the equation
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