(x-2)(13x+46)=0

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Solution for (x-2)(13x+46)=0 equation:



(x-2)(13x+46)=0
We multiply parentheses ..
(+13x^2+46x-26x-92)=0
We get rid of parentheses
13x^2+46x-26x-92=0
We add all the numbers together, and all the variables
13x^2+20x-92=0
a = 13; b = 20; c = -92;
Δ = b2-4ac
Δ = 202-4·13·(-92)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-72}{2*13}=\frac{-92}{26} =-3+7/13 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+72}{2*13}=\frac{52}{26} =2 $

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