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(x-2)(2x+2)=(2)(18)
We move all terms to the left:
(x-2)(2x+2)-((2)(18))=0
determiningTheFunctionDomain (x-2)(2x+2)-218=0
We multiply parentheses ..
(+2x^2+2x-4x-4)-218=0
We get rid of parentheses
2x^2+2x-4x-4-218=0
We add all the numbers together, and all the variables
2x^2-2x-222=0
a = 2; b = -2; c = -222;
Δ = b2-4ac
Δ = -22-4·2·(-222)
Δ = 1780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1780}=\sqrt{4*445}=\sqrt{4}*\sqrt{445}=2\sqrt{445}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{445}}{2*2}=\frac{2-2\sqrt{445}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{445}}{2*2}=\frac{2+2\sqrt{445}}{4} $
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