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(x-2)(2x-5)-(2x-8x=11)=0
We move all terms to the left:
(x-2)(2x-5)-(2x-8x-(11))=0
We add all the numbers together, and all the variables
(x-2)(2x-5)-(-6x-11)=0
We get rid of parentheses
(x-2)(2x-5)+6x+11=0
We multiply parentheses ..
(+2x^2-5x-4x+10)+6x+11=0
We get rid of parentheses
2x^2-5x-4x+6x+10+11=0
We add all the numbers together, and all the variables
2x^2-3x+21=0
a = 2; b = -3; c = +21;
Δ = b2-4ac
Δ = -32-4·2·21
Δ = -159
Delta is less than zero, so there is no solution for the equation
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