(x-2)(2x-5)-(2x2-8x=11)=0

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Solution for (x-2)(2x-5)-(2x2-8x=11)=0 equation: 



(x-2)(2x-5)-(2x^2-8x=11)=0

We move all terms to the left:

(x-2)(2x-5)-(2x^2-8x-(11))=0

We get rid of parentheses

-2x^2+(x-2)(2x-5)+8x+11=0

We multiply parentheses ..

-2x^2+(+2x^2-5x-4x+10)+8x+11=0

We get rid of parentheses

-2x^2+2x^2-5x-4x+8x+10+11=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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