(x-2)(6x-4)=(2x-1)(x-7)

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Solution for (x-2)(6x-4)=(2x-1)(x-7) equation: 



(x-2)(6x-4)=(2x-1)(x-7)

We move all terms to the left:

(x-2)(6x-4)-((2x-1)(x-7))=0

We multiply parentheses ..

(+6x^2-4x-12x+8)-((2x-1)(x-7))=0



We calculate terms in parentheses: -((2x-1)(x-7)), so:

(2x-1)(x-7)

We multiply parentheses ..

(+2x^2-14x-1x+7)

We get rid of parentheses

2x^2-14x-1x+7

We add all the numbers together, and all the variables

2x^2-15x+7

Back to the equation:

-(2x^2-15x+7)



We get rid of parentheses

6x^2-2x^2-4x-12x+15x+8-7=0

We add all the numbers together, and all the variables

4x^2-1x+1=0

a = 4; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·4·1
Δ = -15
Delta is less than zero, so there is no solution for the equation

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