(x-2)(8x+1)=-22(x-2)

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Solution for (x-2)(8x+1)=-22(x-2) equation:


Simplifying
(x + -2)(8x + 1) = -22(x + -2)

Reorder the terms:
(-2 + x)(8x + 1) = -22(x + -2)

Reorder the terms:
(-2 + x)(1 + 8x) = -22(x + -2)

Multiply (-2 + x) * (1 + 8x)
(-2(1 + 8x) + x(1 + 8x)) = -22(x + -2)
((1 * -2 + 8x * -2) + x(1 + 8x)) = -22(x + -2)
((-2 + -16x) + x(1 + 8x)) = -22(x + -2)
(-2 + -16x + (1 * x + 8x * x)) = -22(x + -2)
(-2 + -16x + (1x + 8x2)) = -22(x + -2)

Combine like terms: -16x + 1x = -15x
(-2 + -15x + 8x2) = -22(x + -2)

Reorder the terms:
-2 + -15x + 8x2 = -22(-2 + x)
-2 + -15x + 8x2 = (-2 * -22 + x * -22)
-2 + -15x + 8x2 = (44 + -22x)

Solving
-2 + -15x + 8x2 = 44 + -22x

Solving for variable 'x'.

Reorder the terms:
-2 + -44 + -15x + 22x + 8x2 = 44 + -22x + -44 + 22x

Combine like terms: -2 + -44 = -46
-46 + -15x + 22x + 8x2 = 44 + -22x + -44 + 22x

Combine like terms: -15x + 22x = 7x
-46 + 7x + 8x2 = 44 + -22x + -44 + 22x

Reorder the terms:
-46 + 7x + 8x2 = 44 + -44 + -22x + 22x

Combine like terms: 44 + -44 = 0
-46 + 7x + 8x2 = 0 + -22x + 22x
-46 + 7x + 8x2 = -22x + 22x

Combine like terms: -22x + 22x = 0
-46 + 7x + 8x2 = 0

Factor a trinomial.
(-23 + -8x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-23 + -8x)' equal to zero and attempt to solve: Simplifying -23 + -8x = 0 Solving -23 + -8x = 0 Move all terms containing x to the left, all other terms to the right. Add '23' to each side of the equation. -23 + 23 + -8x = 0 + 23 Combine like terms: -23 + 23 = 0 0 + -8x = 0 + 23 -8x = 0 + 23 Combine like terms: 0 + 23 = 23 -8x = 23 Divide each side by '-8'. x = -2.875 Simplifying x = -2.875

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-2.875, 2}

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