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(x-2)(9+x=)
We move all terms to the left:
(x-2)(9+x-())=0
We calculate terms in parentheses: +(x-2)(9+x-()), so:x=0/2
x-2)(9+x-()
determiningTheFunctionDomain x+x-2)(9-()
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
x=0
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