(x-2)(x+1)=(x-2)(x+2)

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Solution for (x-2)(x+1)=(x-2)(x+2) equation: 



(x-2)(x+1)=(x-2)(x+2)

We move all terms to the left:

(x-2)(x+1)-((x-2)(x+2))=0

We use the square of the difference formula

x^2+(x-2)(x+1)+4=0

We multiply parentheses ..

x^2+(+x^2+x-2x-2)+4=0

We get rid of parentheses

x^2+x^2+x-2x-2+4=0

We add all the numbers together, and all the variables

2x^2-1x+2=0

a = 2; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·2·2
Δ = -15
Delta is less than zero, so there is no solution for the equation

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