(x-2)(x+2)(x-2)=0

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Solution for (x-2)(x+2)(x-2)=0 equation: 


Simplifying
(x + -2)(x + 2)(x + -2) = 0

Reorder the terms:
(-2 + x)(x + 2)(x + -2) = 0

Reorder the terms:
(-2 + x)(2 + x)(x + -2) = 0

Reorder the terms:
(-2 + x)(2 + x)(-2 + x) = 0

Multiply (-2 + x) * (2 + x)
(-2(2 + x) + x(2 + x))(-2 + x) = 0
((2 * -2 + x * -2) + x(2 + x))(-2 + x) = 0
((-4 + -2x) + x(2 + x))(-2 + x) = 0
(-4 + -2x + (2 * x + x * x))(-2 + x) = 0
(-4 + -2x + (2x + x2))(-2 + x) = 0

Combine like terms: -2x + 2x = 0
(-4 + 0 + x2)(-2 + x) = 0
(-4 + x2)(-2 + x) = 0

Multiply (-4 + x2) * (-2 + x)
(-4(-2 + x) + x2(-2 + x)) = 0
((-2 * -4 + x * -4) + x2(-2 + x)) = 0
((8 + -4x) + x2(-2 + x)) = 0
(8 + -4x + (-2 * x2 + x * x2)) = 0
(8 + -4x + (-2x2 + x3)) = 0
(8 + -4x + -2x2 + x3) = 0

Solving
8 + -4x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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