(x-2)(x+2)+4=(x-1)(x+1)+12x

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Solution for (x-2)(x+2)+4=(x-1)(x+1)+12x equation: 



(x-2)(x+2)+4=(x-1)(x+1)+12x

We move all terms to the left:

(x-2)(x+2)+4-((x-1)(x+1)+12x)=0

We use the square of the difference formula

x^2+x^2-4+1+4=0

We add all the numbers together, and all the variables

2x^2+1=0

a = 2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·2·1
Δ = -8
Delta is less than zero, so there is no solution for the equation

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