(x-2)(x+3)(x+1)(x+6)+56=0

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Solution for (x-2)(x+3)(x+1)(x+6)+56=0 equation: 



(x-2)(x+3)(x+1)(x+6)+56=0

We multiply parentheses ..

(+x^2+3x-2x-6)(x+1)(x+6)+56=0

We multiply parentheses ..

(+x^2+3x-2x-6)(+x^2+6x+x+6)+56=0

We move all terms containing x to the left, all other terms to the right

(+x^2+3x-2x-6)(+x^2+6x+x+6)=-56

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