(x-2)(x+4)(x+1)(x+7)=63

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Solution for (x-2)(x+4)(x+1)(x+7)=63 equation: 



(x-2)(x+4)(x+1)(x+7)=63

We move all terms to the left:

(x-2)(x+4)(x+1)(x+7)-(63)=0

We multiply parentheses ..

(+x^2+4x-2x-8)(x+1)(x+7)-63=0

We multiply parentheses ..

(+x^2+4x-2x-8)(+x^2+7x+x+7)-63=0

We move all terms containing x to the left, all other terms to the right

(+x^2+4x-2x-8)(+x^2+7x+x+7)=63

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