(x-2)(x+5)=(x-3)(x+2)

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Solution for (x-2)(x+5)=(x-3)(x+2) equation:



(x-2)(x+5)=(x-3)(x+2)
We move all terms to the left:
(x-2)(x+5)-((x-3)(x+2))=0
We multiply parentheses ..
(+x^2+5x-2x-10)-((x-3)(x+2))=0
We calculate terms in parentheses: -((x-3)(x+2)), so:
(x-3)(x+2)
We multiply parentheses ..
(+x^2+2x-3x-6)
We get rid of parentheses
x^2+2x-3x-6
We add all the numbers together, and all the variables
x^2-1x-6
Back to the equation:
-(x^2-1x-6)
We get rid of parentheses
x^2-x^2+5x-2x+1x-10+6=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1

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