(x-2)(x+6)=9(20)

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Solution for (x-2)(x+6)=9(20) equation:



(x-2)(x+6)=9(20)
We move all terms to the left:
(x-2)(x+6)-(9(20))=0
determiningTheFunctionDomain (x-2)(x+6)-920=0
We multiply parentheses ..
(+x^2+6x-2x-12)-920=0
We get rid of parentheses
x^2+6x-2x-12-920=0
We add all the numbers together, and all the variables
x^2+4x-932=0
a = 1; b = 4; c = -932;
Δ = b2-4ac
Δ = 42-4·1·(-932)
Δ = 3744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3744}=\sqrt{144*26}=\sqrt{144}*\sqrt{26}=12\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12\sqrt{26}}{2*1}=\frac{-4-12\sqrt{26}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12\sqrt{26}}{2*1}=\frac{-4+12\sqrt{26}}{2} $

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