(x-2)(x-1)=(x-2)(x+1)

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Solution for (x-2)(x-1)=(x-2)(x+1) equation: 



(x-2)(x-1)=(x-2)(x+1)

We move all terms to the left:

(x-2)(x-1)-((x-2)(x+1))=0

We multiply parentheses ..

(+x^2-1x-2x+2)-((x-2)(x+1))=0



We calculate terms in parentheses: -((x-2)(x+1)), so:

(x-2)(x+1)

We multiply parentheses ..

(+x^2+x-2x-2)

We get rid of parentheses

x^2+x-2x-2

We add all the numbers together, and all the variables

x^2-1x-2

Back to the equation:

-(x^2-1x-2)



We get rid of parentheses

x^2-x^2-1x-2x+1x+2+2=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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