(x-2)(x-2)=(x-1)(x+1)

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Solution for (x-2)(x-2)=(x-1)(x+1) equation: 



(x-2)(x-2)=(x-1)(x+1)

We move all terms to the left:

(x-2)(x-2)-((x-1)(x+1))=0

We use the square of the difference formula

x^2+(x-2)(x-2)+1=0

We multiply parentheses ..

x^2+(+x^2-2x-2x+4)+1=0

We get rid of parentheses

x^2+x^2-2x-2x+4+1=0

We add all the numbers together, and all the variables

2x^2-4x+5=0

a = 2; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·2·5
Δ = -24
Delta is less than zero, so there is no solution for the equation

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