(x-2)(x-3)(x-4)(x-5)=3024

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Solution for (x-2)(x-3)(x-4)(x-5)=3024 equation: 



(x-2)(x-3)(x-4)(x-5)=3024

We move all terms to the left:

(x-2)(x-3)(x-4)(x-5)-(3024)=0

We multiply parentheses ..

(+x^2-3x-2x+6)(x-4)(x-5)-3024=0

We multiply parentheses ..

(+x^2-3x-2x+6)(+x^2-5x-4x+20)-3024=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x-2x+6)(+x^2-5x-4x+20)=3024

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