(x-2)(x-3)+3(x-1)=(

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Solution for (x-2)(x-3)+3(x-1)=( equation: 



(x-2)(x-3)+3(x-1)=(

We move all terms to the left:

(x-2)(x-3)+3(x-1)-(()=0

We add all the numbers together, and all the variables

(x-2)(x-3)+3(x-1)=0

We multiply parentheses

(x-2)(x-3)+3x-3=0

We multiply parentheses ..

(+x^2-3x-2x+6)+3x-3=0

We get rid of parentheses

x^2-3x-2x+3x+6-3=0

We add all the numbers together, and all the variables

x^2-2x+3=0

a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation

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