(x-2)(x-3)=(x-1)(x+1)

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Solution for (x-2)(x-3)=(x-1)(x+1) equation: 



(x-2)(x-3)=(x-1)(x+1)

We move all terms to the left:

(x-2)(x-3)-((x-1)(x+1))=0

We use the square of the difference formula

x^2+(x-2)(x-3)+1=0

We multiply parentheses ..

x^2+(+x^2-3x-2x+6)+1=0

We get rid of parentheses

x^2+x^2-3x-2x+6+1=0

We add all the numbers together, and all the variables

2x^2-5x+7=0

a = 2; b = -5; c = +7;
Δ = b2-4ac
Δ = -52-4·2·7
Δ = -31
Delta is less than zero, so there is no solution for the equation

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