(x-2)(x-3)=(x-4)(x+9)

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Solution for (x-2)(x-3)=(x-4)(x+9) equation: 



(x-2)(x-3)=(x-4)(x+9)

We move all terms to the left:

(x-2)(x-3)-((x-4)(x+9))=0

We multiply parentheses ..

(+x^2-3x-2x+6)-((x-4)(x+9))=0



We calculate terms in parentheses: -((x-4)(x+9)), so:

(x-4)(x+9)

We multiply parentheses ..

(+x^2+9x-4x-36)

We get rid of parentheses

x^2+9x-4x-36

We add all the numbers together, and all the variables

x^2+5x-36

Back to the equation:

-(x^2+5x-36)



We get rid of parentheses

x^2-x^2-3x-2x-5x+6+36=0

We add all the numbers together, and all the variables

-10x+42=0

We move all terms containing x to the left, all other terms to the right

-10x=-42

x=-42/-10

x=4+1/5

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