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(x-2)(x-3)=(x-5)(x+1)
We move all terms to the left:
(x-2)(x-3)-((x-5)(x+1))=0
We multiply parentheses ..
(+x^2-3x-2x+6)-((x-5)(x+1))=0
We calculate terms in parentheses: -((x-5)(x+1)), so:We get rid of parentheses
(x-5)(x+1)
We multiply parentheses ..
(+x^2+x-5x-5)
We get rid of parentheses
x^2+x-5x-5
We add all the numbers together, and all the variables
x^2-4x-5
Back to the equation:
-(x^2-4x-5)
x^2-x^2-3x-2x+4x+6+5=0
We add all the numbers together, and all the variables
-1x+11=0
We move all terms containing x to the left, all other terms to the right
-x=-11
x=-11/-1
x=+11
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