(x-2)(x-3)=(x-5)(x+1)

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Solution for (x-2)(x-3)=(x-5)(x+1) equation: 



(x-2)(x-3)=(x-5)(x+1)

We move all terms to the left:

(x-2)(x-3)-((x-5)(x+1))=0

We multiply parentheses ..

(+x^2-3x-2x+6)-((x-5)(x+1))=0



We calculate terms in parentheses: -((x-5)(x+1)), so:

(x-5)(x+1)

We multiply parentheses ..

(+x^2+x-5x-5)

We get rid of parentheses

x^2+x-5x-5

We add all the numbers together, and all the variables

x^2-4x-5

Back to the equation:

-(x^2-4x-5)



We get rid of parentheses

x^2-x^2-3x-2x+4x+6+5=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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