(x-2)(x-3)=6+(x-5)(3+x)

Solution for (x-2)(x-3)=6+(x-5)(3+x) equation:

(x-2)(x-3)=6+(x-5)(3+x)

We move all terms to the left:

(x-2)(x-3)-(6+(x-5)(3+x))=0

We add all the numbers together, and all the variables

(x-2)(x-3)-(6+(x-5)(x+3))=0

We multiply parentheses ..

(+x^2-3x-2x+6)-(6+(x-5)(x+3))=0


We calculate terms in parentheses: -(6+(x-5)(x+3)), so:

6+(x-5)(x+3)

determiningTheFunctionDomain
(x-5)(x+3)+6

We multiply parentheses ..

(+x^2+3x-5x-15)+6

We get rid of parentheses

x^2+3x-5x-15+6

We add all the numbers together, and all the variables

x^2-2x-9

Back to the equation:

-(x^2-2x-9)


We get rid of parentheses

x^2-x^2-3x-2x+2x+6+9=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5