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(x-2)(x-4)(x+3)(x+5)=120
We move all terms to the left:
(x-2)(x-4)(x+3)(x+5)-(120)=0
We multiply parentheses ..
(+x^2-4x-2x+8)(x+3)(x+5)-120=0
We multiply parentheses ..
(+x^2-4x-2x+8)(+x^2+5x+3x+15)-120=0
We move all terms containing x to the left, all other terms to the right
(+x^2-4x-2x+8)(+x^2+5x+3x+15)=120
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