(x-2)(x-4)(x-5)(x-7)=72

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Solution for (x-2)(x-4)(x-5)(x-7)=72 equation: 



(x-2)(x-4)(x-5)(x-7)=72

We move all terms to the left:

(x-2)(x-4)(x-5)(x-7)-(72)=0

We multiply parentheses ..

(+x^2-4x-2x+8)(x-5)(x-7)-72=0

We multiply parentheses ..

(+x^2-4x-2x+8)(+x^2-7x-5x+35)-72=0

We move all terms containing x to the left, all other terms to the right

(+x^2-4x-2x+8)(+x^2-7x-5x+35)=72

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