(x-2)(x-48)=0

Solution for (x-2)(x-48)=0 equation:

(x-2)(x-48)=0

We multiply parentheses ..

(+x^2-48x-2x+96)=0

We get rid of parentheses

x^2-48x-2x+96=0

We add all the numbers together, and all the variables

x^2-50x+96=0

a = 1; b = -50; c = +96;
Δ = b2-4ac
Δ = -502-4·1·96
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-46}{2*1}=\frac{4}{2}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+46}{2*1}=\frac{96}{2}
=48
$