(x-2)(x-5)=(x-1)(X-4)

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Solution for (x-2)(x-5)=(x-1)(X-4) equation: 



(x-2)(x-5)=(x-1)(x-4)

We move all terms to the left:

(x-2)(x-5)-((x-1)(x-4))=0

We multiply parentheses ..

(+x^2-5x-2x+10)-((x-1)(x-4))=0



We calculate terms in parentheses: -((x-1)(x-4)), so:

(x-1)(x-4)

We multiply parentheses ..

(+x^2-4x-1x+4)

We get rid of parentheses

x^2-4x-1x+4

We add all the numbers together, and all the variables

x^2-5x+4

Back to the equation:

-(x^2-5x+4)



We get rid of parentheses

x^2-x^2-5x-2x+5x+10-4=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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