(x-2)(x-6)(x+1)(x+5)=-180

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Solution for (x-2)(x-6)(x+1)(x+5)=-180 equation: 



(x-2)(x-6)(x+1)(x+5)=-180

We move all terms to the left:

(x-2)(x-6)(x+1)(x+5)-(-180)=0

We add all the numbers together, and all the variables

(x-2)(x-6)(x+1)(x+5)+180=0

We multiply parentheses ..

(+x^2-6x-2x+12)(x+1)(x+5)+180=0

We multiply parentheses ..

(+x^2-6x-2x+12)(+x^2+5x+x+5)+180=0

We move all terms containing x to the left, all other terms to the right

(+x^2-6x-2x+12)(+x^2+5x+x+5)=-180

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