(x-2)(x-7)=(x-3)(x+6)

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Solution for (x-2)(x-7)=(x-3)(x+6) equation: 



(x-2)(x-7)=(x-3)(x+6)

We move all terms to the left:

(x-2)(x-7)-((x-3)(x+6))=0

We multiply parentheses ..

(+x^2-7x-2x+14)-((x-3)(x+6))=0



We calculate terms in parentheses: -((x-3)(x+6)), so:

(x-3)(x+6)

We multiply parentheses ..

(+x^2+6x-3x-18)

We get rid of parentheses

x^2+6x-3x-18

We add all the numbers together, and all the variables

x^2+3x-18

Back to the equation:

-(x^2+3x-18)



We get rid of parentheses

x^2-x^2-7x-2x-3x+14+18=0

We add all the numbers together, and all the variables

-12x+32=0

We move all terms containing x to the left, all other terms to the right

-12x=-32

x=-32/-12

x=2+2/3

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