(x-2)*(x+2)*(x+2)-(x+2)=0

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Solution for (x-2)*(x+2)*(x+2)-(x+2)=0 equation: 



(x-2)*(x+2)(x+2)-(x+2)=0

We get rid of parentheses

(x-2)*(x+2)(x+2)-x-2=0

We multiply parentheses ..

(x-2)*(+x^2+2x+2x+4)-x-2=0

We add all the numbers together, and all the variables

(x-2)*(+x^2+2x+2x+4)-1x-2=0

We move all terms containing x to the left, all other terms to the right

(x-2)*(+x^2+2x+2x+4)-1x=2

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