(x-2)+(10x-20)+(20x-40)=1/2(62x)-99

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Solution for (x-2)+(10x-20)+(20x-40)=1/2(62x)-99 equation: 


x in (-oo:+oo)

x+10*x+20*x-40-20-2 = 62*(1/2)*x-99 // - 62*(1/2)*x-99

x+10*x+20*x-(62*(1/2)*x)-40-20-2+99 = 0

x+10*x+20*x-31*x-40-20-2+99 = 0

37 = 0

x belongs to the empty set

x belongs to the empty set

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