(x-2)+(2x-11)=(6x-15)

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Solution for (x-2)+(2x-11)=(6x-15) equation: 



(x-2)+(2x-11)=(6x-15)

We move all terms to the left:

(x-2)+(2x-11)-((6x-15))=0

We get rid of parentheses

x+2x-((6x-15))-2-11=0



We calculate terms in parentheses: -((6x-15)), so:

(6x-15)

We get rid of parentheses

6x-15

Back to the equation:

-(6x-15)



We add all the numbers together, and all the variables

3x-(6x-15)-13=0

We get rid of parentheses

3x-6x+15-13=0

We add all the numbers together, and all the variables

-3x+2=0

We move all terms containing x to the left, all other terms to the right

-3x=-2

x=-2/-3

x=2/3

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