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(x-2)+(x+2)=(2x-4)+(x+2)
We move all terms to the left:
(x-2)+(x+2)-((2x-4)+(x+2))=0
We get rid of parentheses
x+x-((2x-4)+(x+2))-2+2=0
We calculate terms in parentheses: -((2x-4)+(x+2)), so:We add all the numbers together, and all the variables
(2x-4)+(x+2)
We get rid of parentheses
2x+x-4+2
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
2x-(3x-2)=0
We get rid of parentheses
2x-3x+2=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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