(x-2)+(x+4)=(X+3)+(X+6)+(X+4)

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Solution for (x-2)+(x+4)=(X+3)+(X+6)+(X+4) equation: 



(x-2)+(x+4)=(x+3)+(x+6)+(x+4)

We move all terms to the left:

(x-2)+(x+4)-((x+3)+(x+6)+(x+4))=0

We get rid of parentheses

x+x-((x+3)+(x+6)+(x+4))-2+4=0



We calculate terms in parentheses: -((x+3)+(x+6)+(x+4)), so:

(x+3)+(x+6)+(x+4)

We get rid of parentheses

x+x+x+3+6+4

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

2x-(3x+13)+2=0

We get rid of parentheses

2x-3x-13+2=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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