(x-2)+x+(2(x-2))=58

Solution for (x-2)+x+(2(x-2))=58 equation:

(x-2)+x+(2(x-2))=58

We move all terms to the left:

(x-2)+x+(2(x-2))-(58)=0

We add all the numbers together, and all the variables

x+(x-2)+(2(x-2))-58=0

We get rid of parentheses

x+x+(2(x-2))-2-58=0


We calculate terms in parentheses: +(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

+(2x-4)


We add all the numbers together, and all the variables

2x+(2x-4)-60=0

We get rid of parentheses

2x+2x-4-60=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16