(x-2)-(x-3)=-2(x-2)+5x+6

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Solution for (x-2)-(x-3)=-2(x-2)+5x+6 equation: 



(x-2)-(x-3)=-2(x-2)+5x+6

We move all terms to the left:

(x-2)-(x-3)-(-2(x-2)+5x+6)=0

We get rid of parentheses

x-x-(-2(x-2)+5x+6)-2+3=0



We calculate terms in parentheses: -(-2(x-2)+5x+6), so:

-2(x-2)+5x+6

We add all the numbers together, and all the variables

5x-2(x-2)+6

We multiply parentheses

5x-2x+4+6

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

-(3x+10)+1=0

We get rid of parentheses

-3x-10+1=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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